a father is 4 times his sons age. after 5yrs, he will be 3 times his sons age find present age. linear equation. pls answer its urgent
Answers
Step-by-step explanation:
Let x yr be the present age of father and y yr be the present age of son.
Four years hence, it has relation by given condition,
(x + 4) = 4(y + 4)
⇒ x-4y = 12 …(i)
and x = 6y …(ii)
On putting the value of x from Eq. (ii) in Eq. (i), we get
6y-4y=12
⇒ 2y = 12
⇒ y = 6
When y = 6, then x = 36
Hence, present age of father is 36 yr and age of son is 6 yr.
or
Answer:
let \: sons \:present \: age \: be \: xletsonspresentagebex
fathers \: present \: age \: = 4xfatherspresentage=4x
after \: 5 \: yearsafter5years
sons \: age \: = x + 5sonsage=x+5
fathers \: age \: = 4x + 5fathersage=4x+5
atqatq
4x + 5 = 3(x + 5)4x+5=3(x+5)
4x + 5 = 3x + 154x+5=3x+15
4x - 3x = 15 - 54x−3x=15−5
x = 10x=10
sons \: present \: age \: = x = 10 \: yearssonspresentage=x=10years
fathers \: present \: age \: = 4x = 4 \times 10 = 40 \: years fathers presentage=4x=4×10=40years
hope it helps..........
for what u are waiting mark me .......plz .....
Answer: