Question

a father is 4 times old as his son. the sum of their age is 40 years. find their ages

Answer 1

Answer:

Step-by-step explanation:

Let the father's age be x and the son's age be y.

Given,

$x=4y$

and $x+y=40$ ------> 1

Now, substituting $x=4y$ in eqn. 1

we get,

$4y+y=40\\5y=40\\y=\frac{40}{5}\\ y=8 years\\=>x=4y=4(8)=32 years$

Answer 2

Hey, Mate.....!!!!

•●○◇◇》》ANSWER《《◇◇○●•

$let \: son</u><u>'</u><u>s</u><u> \: age \: be \: x \\ so ........ \\ father</u><u>'</u><u>s</u><u> \: age \: be \: 4x \\ </u><u>A</u><u>T</u><u>Q</u><u>:</u><u> - \\ 4x + x = 40 \\ 5x = 40 \\ x = \frac{40}{5} \\ x = 8 \\ \\ </u><u>T</u><u>herefore</u><u>,</u><u> \: son</u><u>'</u><u>s</u><u> \: age \: is \: 8 \: years \: \\ and..... \: father</u><u>'</u><u>s</u><u> \: age \: is \: 4x \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 4 \times 8 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 32years.$