Question

A father is 4 times old as his son . The sum of their age is 40 years . Find their ages .

Answer 1

Answer:

let the age of son be x

then the age of father 4x

sum of their age x+4x=40

5x=40

x=40/5

x=8

Answer 2

Step-by-step explanation:

Let the age of the father be x and let the age of his son be y

According to the question

x = 4y          -(1)

x + y = 40    -(2)

substituting equation (1) in (2)

4y + y = 40

5y = 40

y = 40/5

y = 8

y = 8 in equation (1)

x = 4*8

x = 32

therfore the age of the father is 32 and the age of his son is 8 years