Math, asked by manu331, 1 year ago

a father is 4 times the age of his daughter who is X year old 4 years later the father's age become 3 times the age of his daughter find the present age of the father

Answers

Answered by Ispa
2
Hii...
Father=4x
Daughter=x
After 4 years-:
Father=4x(4+3)
Daughter=x+3
=4x(7)=x+3
28x=x+3
28x-x=3
27x=3
x=27/3
x=9
Daughter=9
Father=9×4=36
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