Question

A father is 40 years old and his son is 16 years old after how many years will the father's age be twice that of his son's age​

Answer 1

Let the present age of the son be x years

Then father's age will be (x+30) years

Given after 12 years father will be three times as old as his son

Therefore,

(x+12)3=x+30+12

3x+36=x+42

3x−x=42−36

2x=6

x=3

x+30=3+30=33

So, the present age of son is 3 years and present age of the father is 33 years