Question

a father is 45 year elder than his son.in 15 years.the father. will be three times as old as his son .find their present age?

Answer 1

Answer:

father 75 and son 30

Step-by-step explanation:

45+x __x

father__son

(45+x)+15yrs =3x

60+x=3x

2x =60

x=30

father=x +45=30+45=75

son=x=30

Answer 2

GIVEN :-

A father is 45 years elder than his son. After 15 years his age will be thrice as the age of his son now.

SOLUTION :-

Let the age of son be '' x ''.

Then, father's age will be " x + 45 ".

After 15 years :-

• Father's age = Thrice the son's present age.

EQUATION :-

=> (x + 45) + 15 = 3x

=> x + 45 + 15 = 3x

=> 3x = x + 45 + 15

=> 3x - x = 45 + 15

=> 2x = 60

=> x = 60 / 2

=> x = 30.

Therefore,

• Son's age = x = 30 years
• Father's age = x + 45 years = 75 years.