A father is 45 years elder then his son in 15 years the father will be three times as old as his son find their present age
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Answered by
9
let the age of son be 'x'
father's age = x+45
15 years from now
father's age = (x+45)+15 = x+65
son's age = x+15
according to given condition
3*(x+15) = x+65
3x+45 = x+65
3x-x = 65-45
2x = 20
x = 10
son's age = x = 10
father's age = x+45 = 10+45 = 55
Answered by
6
Answer:
let son's age= x
father's age= x+45
after 15years
father's age = (x+45)+15=x+60
given condition
3(x+15)=x+60
3x+45=x+60
3x-x=60-45
2x=15
x=15/2
x=7.5
therefore
son's age =7.5years
father's age =7.5+45=52.5years
hope it can use
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