A father is 6 times old as his son.4 years later he will be four timesas old as his son. find the present ages
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Let the age of son be x years, then age of father be 6x years
after 4 years
age of son = x+4 years
age of father= 6x+4 years
acc. to question
after 4 years age if fater will be 4 times as old as his son
6x+4= 4(x+4)
6x+4= 4x+16
6x-4x= 16-4
2x= 12
x= 12/2= 6
so
present age of son = 6 years
present age of father= 36 years
after 4 years
age of son = x+4 years
age of father= 6x+4 years
acc. to question
after 4 years age if fater will be 4 times as old as his son
6x+4= 4(x+4)
6x+4= 4x+16
6x-4x= 16-4
2x= 12
x= 12/2= 6
so
present age of son = 6 years
present age of father= 36 years
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