A father is 6 times older than his son. After 4 years, he will be only 4 times as old as his son. What are their present ages?
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Given :
- Father is 6 times older than his son.
- After 4 years, father's age will be 4 times as old as son's age.
To Find :
- Present age of Father
- Present age of Son
Solution :
Let the present age of father be x years.
Let the present age of son be y years.
Case 1 :
The age of Father, x is 6 times the age of son, y.
Equation :
Case 2 :
After 4 years, father's age, x will be 4 times the age of son.
Age of father after 4 year, (x+4) years.
Age of son after 4 year, (y+4) years.
Equation :
Now, subtract equation (1) from (2),
Substitute, y = 6 in equation (1),
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