Question

A father is 7 times as old as his son . 2 years ago the father was 13 times as old as his son . Find their present age .​

Answer 1

Answer:

son's age = 4

father's age = 28

Step-by-step explanation:

let father's present age be x

son's present age be y

x = 7y equ (1)

before 2 years

father's age = x - 2

son's age = y - 2

x - 2 = 13(y - 2)

x - 2 = 13y - 26

7y - 2 = 13y - 26 (since x = 7y)

13y - 7y = 26 - 2

6y = 24

y = 24/6 = 4

x = 7y = 7 × 4 = 28

father's present age = x = 28

son's present age = y = 4

hope this answer helps you