A father is 7 times as old as his son. Three years
ago, the father was 13 times as old as his son.
What are their present ages?
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Answers
Answered by
3
Let the present age of the son be x and that to of his father which is 7 times =7x
Then, 2 years ago their ages :
(x-2) of son
(7x-2) of father
Given, 13(x−2)=7x−2
Then,
13x−26=7x−2
=13x−7x=26−2
6x=24
or x=4 and that of his father = 28 years
ageofson=x=4years
ageoffather=7x=28years
Answered by
7
Given that , A father is 7 times as old as his son. Three years ago, the father was 13 times as old as his son.
Exigency To Find : Their [ Father and Son ] Present ages ?
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
❍ Let's say that , Present age of Father be x yrs .
Given that ,
⠀⠀⠀▪︎⠀A father is 7 times as old as his son.
Therefore,
- Present age of Father is 7x yrs .
⠀⠀⠀⠀⠀⠀⠀⠀☆ Before 3 years their ages :
- Age of Father will be ( 7x - 3 ) yrs .
- Age of Son will be ( x - 3 ) yrs .
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
⠀⠀⠀⠀⠀━━━ Three years ago , the father was 13 times as old as his son.
Therefore,
- Present age of Son is x = 7 yrs &
- Present age of Father is 7x = 7(7) = 49 yrs .
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