Question

A father is 7 times as old as his son. Two years ago father age is 13 times as old as his son. What are their present ages?​

Answer 1

Step-by-step explanation:

Present age of son = x yrs.

Present age of Father = 7(x) yrs.

A/q, Two years ago son age = x-2 yrs.

Two years ago Father age = 7x-2 yrs.

7x-2 = 13(x-2)

7x-2 = 13x-26

-2+26 = 13x-7x

6x = 24

x = 4

P age of son = x = 4 yrs.

P age of Father = 7x = 28 yrs.

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Answer 2

Step-by-step explanation:

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