Question

a father is 7 times as old as his son two years ago the father of was 13 times as old as his son what are their present age​

Answer 1

Answer:

Let the age of son be x and father be y

y= 7x

two years ago

13(x -2 )= y-2

13x - 26 +2 = y

13x -24 = 7x

13x -7x = 24

6x = 24 .

x= 4

y = 7(4) = 28 years

Answer 2

Let present age of father be M and present age of son be N.

☞ A father is 7 times as old as his son.

=> M = 7N _________(eq 1)

☞ Two years ago the father of was 13 times as old as his son.

• A.T.Q.

=> (M - 2) = 13(N - 2)

=> M - 2 = 13N - 26

=> M - 13N = - 26 + 2

=> M - 13N = - 24 ___________(eq 2)

=> (7N) - 13N = - 24 [From (eq 1)]

=> - 6N = - 24

=> N = 4

• Put value of N in (eq 1)

=> M = 7(4)

=> 28

____________________________

Present age of father = M = 28 years

Present age of son = N = 4 years

_______________[ANSWER]