Question

A father is 7 times as old as his son
Two years ago the father was 13 times old as his Son
what are their present ages.
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

let the present age of father be X and let the present age of son be Y .

according to first condition ,

x+y = 7

according to second condition ,

2(x+y) = 13

2x+2y=13.

multiplying equation 1 by number 2

2x+2y =7.

2x+2y =13

- 2x+2y=7

__________

x = 6

substituting x = 6 in equation 1

x+y = 7

6 + y = 7

y = 7-6

y = 1 .