Question

A father is 7 times as old as his son. Two years ago, the father was 13 times as old as his son. Find their present ages.

Answer 1

Answer:

Let the present age of the son be x and that to of his father which is 7 times =7x

Then, 2 years ago their ages :

(x-2) of son 

(7x-2)  of father

Given, 13(x−2)=7x−2

Then,

13x−26=7x−2

=13x−7x=26−2

6x=24

or x=4 and that of his father = 28 years

ageofson=x=4years

ageoffather=7x=28years

Step-by-step explanation:

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