Question

A father is 7 times as old as his son , two years ago the Father was 13 times as old as his son .then the present age of son in ............ y​

Answer 1

DAD=7X WHEN THE SON'S AGE IS X NOW.

2 YEARS AGO THEY WERE:

DAD=(7X-2) & THE SON=(X-2)

SO WE HAVE:

7X-2=13(X-2)

7X-2=13X-26

7X-13X=-26+2

-6X=-24

X=-24/-6

X=4 THE AGE OF THE SON NOW.

THUS THE DAD=7*4=28 YEARS OLD NOW.

PROOF:

7*4-2=13(4-2)

28-2=13*2

26=26