Question

a father is 7 times as old as his son two years ago the father was 13 times as old as his son how old are they now

Answer 1

Father age is 28 & son age is 4

Answer 2

$\bold {\Huge {\boxed {\boxed{Answer:}}}}$

At present,

$<b><i>Let the son's age be x Then the father's age =7x$

Now,2 years ago ,

$<b><i>Son's age =(x-2) And Father's age=(7x-2)$

$<b><underline>Now,According to question$

$\implies$$<b><i>7x-2=13 (x-2)$

$\implies$$<b><i>7x-2=13x-26$

$\implies$$<b><i>7x-13x=-26+2$

$\implies$$<b><i>-6x=-24$

$\implies$$\bold{x=}$$\cancel{\bold{\frac{-24}{-6}}}$

$\therefore$$\bold {x=4}$

$<b><u>Present son's age=x=4 years . Present father's age =7x=7×4=28 years</b></u>$

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