Question

A father is 7 times as old as his son two years ago the father was 13 times as old as his son what is their present age

Answer 1

let the present age of son is x and of father is 7x
two years ago:-
age of son= x -2
age of father= 7x-2

therefore 7x-2 = 13(x-2)
present age of father is 28 and of son is 4

Answer 2

Father's age = ( 7x - 2 ) years

According to the problem given,

7x - 2 = 13 ( x - 2 )

7x - 2 = 13x - 26

7x - 13x = -26 + 2

-6x = -24

x = ( -24 ) / ( -6 )

x = 4

Therefore ,

At present ,

Son age = x = 4years

Father's age = 7x = 7 × 4 = 28years

I hope this helps you