Question

A father is 7 times as old as his son. Two yrs ago,the father was 13 times as old as his son. What are their present ages.(explain with step by step)​

Answer 1

Answer:

let son's present age = x

father's present age = 7x

son's age before 2 years (x - 2)

father's age before 2 years (7x - 2)

as per the given condition,

(7x - 2) = 13 (x - 2)

7x - 2 = 13x - 26

7x - 13x = -26 + 2

- 6x = - 24

x = 4

therefore son's present age is 4 years

father's present age is 7x = 7×4=28 years

Answer 2

Step-by-step explanation:

let son's age be x

father age is 7x

ATQ, 7x-2 = 13x - 26

6x = 24

x = 4

present age of son is 4 and father is 28