Question

A father is 7 times as older as his son. Two years ago, the father was 13 times as older as his son. How old they are now?

Answer 1

let son age is x
so his father age is 7x

again ,
( 7x-2) =13( x -2)

7x -2 =13x -26

6x =24

x =4

so, father age =28 years
and his son age =4 years

Answer 2

Son age be x
Father age=7x
Two years ago
Father age=7x-2
Son age=x-2
7x-2=13(x-2)
7x-2=13x-26
-6x=-24
x=4
Son's age=4
Father's age=28