Question

a father is 7 times old as his son two years ago the father was13 times as old as his son what are their present age

Answer 1

Answer:

789

Step-by-step explanation:

345+78- 567890

then, minus it

567890-56

234

ans.23445

Answer 2

Answer:

Let the present age of the son be x and that to of his father which is 7 times =7x

Then, 2 years ago their ages :

(x-2) of son

(7x-2) of father

Given, 13(x − 2) = 7x - 2 -

Then,

13x 267x - 2

13x7x 26 - 2 =

6x - 24

or x=4 and that of his father = 28 years

age of son = x = 4 years

age of father = 7x = 28 years