A FATHER IS 7 TIMES OLD AS HIS SON. TWO YEARS AGO,THE FSTHER WAS 13 TIMES OLD AS HIS SON.FIND THERE PRESENT AGES?
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Step-by-step explanation:
Let the son's age be x.
His father's age would be 7x.
Two years ago father's age was 7x - 2 .
So,
7x - 2 = 13 (x -2 ) [x -2 is the son's age two years ago]
7x - 2 = 13x - 26
-2 + 26 = 13x - 7x
24 = 6x
x = 24/6
x = 4
Hence father's age is 7 * 4 = 28 years
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