Question

A FATHER IS 7 TIMES OLD AS HIS SON. TWO YEARS AGO,THE FSTHER WAS 13 TIMES OLD AS HIS SON.FIND THERE PRESENT AGES?

Answer 1

Answer:

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Step-by-step explanation:

Let the son's age be x.

His father's age would be 7x.

Two years ago father's age was 7x - 2 .

So,

7x - 2 = 13 (x -2 ) [x -2 is the son's age two years ago]

7x - 2 = 13x - 26

-2 + 26 = 13x - 7x

24 = 6x

x = 24/6

x = 4

Hence father's age is 7 * 4 = 28 years