Question

a father is 7times as old as his son. Two years ago the father was 13 years as old as his son . How old are they now​

Answer 1

Answer:

Son: 4 years old

Father: 28 years old

Step-by-step explanation:

DAD=7X WHEN THE SON'S AGE IS X NOW.

2 YEARS AGO THEY WERE:

DAD=(7X-2) & THE SON=(X-2)

SO WE HAVE:

7X-2=13(X-2)

7X-2=13X-26

7X-13X=-26+2

-6X=-24

X=-24/-6

X=4 THE AGE OF THE SON NOW.

THUS THE DAD=7*4=28 YEARS OLD NOW.

Answer 2

Answer:

Step-by-step explanation:

let son be y

let father be x

x + 0 = 7y

x - 2 = 13 + y - 2

x = 7y

x = y + 13

7y = y + 13

6y = 13

y = 2.1

substitute y into first equation

x = 7 × 2.1

 = 14.7