Question

A father is 8 times as old as his son.2 years ago ,the father was 10 times as old as his son. How old are they now.​

Answer 1

father is 8 times as old as his son.2 years ago ,the father was 10 times as old as his son. How old are they now.

Answer 2

Answer:

Present age of father is 49 years and that of his son is 7 years.

Step-by-step explanation:

Let the present age of the son be x.

Let the father's present age be y.

One year ago, y−1=8(x−1)

⇒y−1=8x−8

⇒y=8x−7

Now applying the condition, we get

(8x−7)=x

2

⇒x

2

−8x+7=0

⇒(x−1)(x−7)=0

⇒x=1 or x=7

Hence, the present age of son is either 1 year or 7 years.