A father is age is three times the sum of
the ages of his two children After
5 years he age will be the time
the sum of their cages find the present
ages of the father
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Step-by-step explanation:
LET FATHER AND SUM OF HIS SONS PRESENT AGE BE X AND Y YEARS RESPECTIVELY.
X=3*Y ......................1
AFTER 5 YEARS
X + 5 = 2(Y+ 5)
X-2Y= 5....................................................2
USING EQ 1 AND 2
Y=5
X=15
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