Question

A father is as four times as old as his son is son is now, 10years later, the father's age will be twice the son's age added to 6.
Find their present ages

Answer 1

Step-by-step explanation:

Let Present age of Son= X years.

Father is 4 times the age of Son

Father Present age=4x years

After 10 years

Son Age will be=x+10 years

Father Age will be=4x +10 years

Now Question saying father age after 10 years (4x+10) is Twice the son age added to 6 after 10 years (x+10)

Means

2(Son's age after 10 years)+6=Father Age after 10 years

2(x+10)+6=4x+10

2x+20+6=4x+10

2x-4x=10-26

-2x=-16

x=-16/-2

x=8 years

Present Age of Son=x=8 years

Present age of Father=4x=4×8=32 years

Son=8 years

Father=32 years

Answer 2

Answer:

Sons age is 8 years and father's age is 32 years.

To Find :- Present age of son and his father.

Explanation :-

Let the present age of son be x and father be y years respectively.

According to the given statement

Fathers age is 4 time to his son = 4x

10 years later, Age of his son will be (x + 10) and father's age will be (y+ 10) years

The father's age will be twice the age of sons age added to 6

Therefore, the given statement will be represented as

2(x + 10) + 6 = (4x + 10)

2x + 26 = 4x + 10

2x - 4x = 10 - 26

- 2x = - 16

x = -2/-16

x = 8

Present age of son is x

Therefore, the age of son is 8 years.

Age of his father 4x

4(8)

32 years.