Math, asked by bawskarsangita95, 11 months ago

a father is fifty one and his son is 16.in how many years will the father be twice as old as his son?​

Answers

Answered by pavan15sai
0

Answer:

Step-by-step explanation:

son = 16+x

51+x= 2(16+x)

51+x =32+ 2x

2x-x=51-32 =after 19 years father be twice opder than the son

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