Question

a father is four times as old as his son five years ago he was seven times as old as his son find the present age

Answer 1

Let son's age be x then father's age is 3x
Five years ago, father's age = 3x-5 and son's age x-5
So, 3x-5 = 4(x-5)
=> 3x-5 = 4x-20
=> x = 15

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