Question

A father is four times as old as his son. in 18 years he will be only twice as old as his son. find their ages​

Answer 1

Answer:

Good day dear..hope it helps..

Answer 2

Answer:

6

Step-by-step explanation:

father age =4x

son age =x

After 18 years

son will be(x+18)

fathers age will be(4x +18)

then

2(x+18)=(4x+18)

2x+18=4x+18

6x=36

36/6

=6