Question

A father is four times as old as his son. in16 years, he will only be twice as old, find their
ages​

Answer 1

Step-by-step explanation:

let the father age be x

and the sons age be y

according to the first equation

x=4y

in 16 years ...

x+16= (y+16)×2

putting both the equations together

4y+16=(y+16)×2

4y=(y+16)×2-16

4y= 2y +32-16

4y-2y=32-16

2y=16

y=8

putting y=8 in the first equation

x=4y

x=4×8

x=32