Question

a father is four times as old as his son. know four years time he will be three times as old as his son. what are their present age

Answer 1

Let present age of son and his Father is
Son age be y
And, Father age be 4y
So, the equation becomes
y = 4y
After four years
y + 4 = 4y + 4
Father is three times as old as his son
So, their ages become
3 ( y + 4) = (4y + 4)
3y + 12 = 4y + 4
12 - 4 = 4y - 3y
y = 8
So,
Age of Son = y
= 8 years old
Age of Father = 4y
= 4 × 8
= 32 years old
Hope, it is helpful

Answer 2

father let be x
present age y
equation

4x+y = 1
4x-y=3
______
_ + _
2y =2

y = 1

let go 1 equation
4x+y= 1
4x +1=1
4x=1-1
x=1/4

child age is1/4 times
thank you

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