Question

A father is four times as old as his son now. After 24 years he would only be twice as old as his son. what are the present ages of the father and the son?​

Answer 1

Step-by-step explanation:

Let the present age of the son = x years

Present age of the father = 4x years

After 20 years,

Son’s age will be (x + 20) years

and Father’s age will be (4x + 20) years

According to the condition,

4x+20=2(x+20)

\Rightarrow\ 4x+20=2x+40

\Rightarrow4x-2x=40-20

2x=20

⇒x=\frac{20}{2}

⇒x=10

∴Present age of the son is10 years and

Present age of the father is = 4x=4\times10=40 years.

Answer 2

Answer:

Father's age = 48 years

Father's age = 48 yearsSon's age = 12 years

Step-by-step explanation:

Let assume Son's age = X year

so, Father's age (Y) = 4X year

According to the Condition,

2(X+24) = Y+24

or, 2x +48 = 4x + 24

or, 2X = 24

or, X= 12

So, Y = 4X = (4×12) = 48

Therefore the present age of the father is 48 years and the age of the son is 12 years.