Question

A father is four times as old as his son now.if the sum of their ages ten years ago was sixty, find their present ages.

Answer 1

Step-by-step explanation:

let son age be x

let father age be 4x

x+10+4x=60

5x=50

x=10

Answer 2

Answer:

Son age= x

father age= 4x

ten years ago,

x +4x= 60

5x=60

x=60/5

x=12

sons age = 12

dad age= 12 x 4 = 48

present

son age = 12 + 10 = 22

dad age= 48 + 10 = 58

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