Question

a father is four times his son's age.7 years ago he was 11 times his son's age.find the present age of father and son ​

Answer 1

Answer:

let the son's age be X

then father's age will be 4x

before 7 years means son's age will be x-7

then father's age is 11(x-7)

X+4x=11(x-7)+x-7

5x=11x-77+x-7

5x=12x-84

84=12x-5x

84=7x

X=12

then the son's age is 12 years and father's age will be 12(4)=48 years