Question

a father is four times the age of his son 5 years hence father will be three times the age of his son find their present ages​

Answer 1

Solution:-

letfather's age = x

son's age = y

5 years hence, age of father = x+5 

                                 

age of son = y+5

So (x+5) = 3(y+5)

⇒ x =3y+10

5 years ago, age of father = x-5 

                               

 age of son = y-5

So x-5 = 7(y-5)

⇒3y + 10 - 5 = 7y - 35

⇒ 4y = 40

⇒y = 10  age of son

   x = 3y +10 = 40

son age = 10 year

father's age= 40 year

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@GauravSXena01

Answer 2

Answer:

Let the present age of son be x years and present age of father will be 4x years.

According to Question now,

➳ 3(x + 5) = 4x + 5

➳ 3x + 15 = 4x + 5

➳ 15 - 5 = 4x - 3x

➳ x = 10 years

Therefore,

Present age of son = x = 10 years

Present age of father = 4x = 40 years