Question

a father is is 9 times as old as his son after 3 years he will be 5 times a s old as his son find their present ages.
With steps

Answer 1

✯ Father's present age=45 years✯

✯ Son's present age = 5 years✯

Step-by-step explanation:

Given:

• A father is 9 times as old as his son.
• After 3 years, he will be 5 times as old as his son.

To find:

• Their present ages.

Solution:

Let the present age of son be x years.

✯ A father is 9 times as old as his son.

Then,

• Present age of father = 9x years

✯${\underline{\sf{According\:to\:the\: question,}}}$

• After 3 years, he will be 5 times as old as his son.

After 3 years,

• Father's age = (9x+5) years
• Son's age = (x+5) years

$\implies$9x+5=5(x+5)

$\implies$9x+5=5x+25

$\implies$9x-5x=25-5

$\implies$4x=20

$\implies$x=5

† Present age of son = 5 years

† Present age of father = 9×5 = 45 years

________________

† Verification :

• Father's present age = 45 years
• Son's present age = 5 years

After 5 years,

• Father's age = (45+5) = 50 years
• Son's age = (5+5) = 10 years

A/Q,

Father's age = 5× son's age

→ 50 = 5×10

→ 50 = 50

Hence Verified !

Answer 2

Answer:

Step-by-step explanation:

Let the sons age be x

then fathers age is 9x

After 3 yrs

9x+3=5(x+3)

9x+3=5x+15

9x-5x=15-3

4x=12

x=12/4

x=3

Therefore,their present ages are

Son=3

Dad=27