Math, asked by Anonymous, 11 months ago

A father is now three times as old as his son. Eight years ago, the father was five times as old as his son. What is the present age of the son?

Answers

Answered by saivivek16
3

Step-by-step explanation:

Aloha !

3x-8=5(x-8)

3x-8=5x-40

5x-3x=40-8

2x=32

x=32/2

x=16

Thank you

Answered by SwaggerGabru
2

Answer:

Let son's age be x then father's age is 3x

Five years ago, father's age = 3x-5 and son's age x-5

So, 3x-5 = 4(x-5)

=> 3x-5 = 4x-20

=> x = 15

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