Question

A father is now three times as old as his son
Eive years back, he was four times es old as
his son. The age of the son in years,
(A) 10
(B) 12
(D) 18
​

Answer 1

Answer:

Let son's age be x then father's age is 3x

Five years ago, father's age = 3x-5 and son's age x-5

So, 3x-5 = 4(x-5)

=> 3x-5 = 4x-20

=> x = 15

Answer 2

Answer:

what is c option, if it is 15 it is correct

Step-by-step explanation:

LET PRESENT AGE OF SON =X

AND PRESENT AGE OF FATHER=Y

FROM QUESTION

Y=3X

=>3X-Y=0 ====>1

AGE OF SON BEFORE 5 YEARS = X-5

AGE OF FATHER BEFORE 5 YEARS=Y-5

FROM QUESTION

Y-5=4(X-5)

=>Y-5=4X-20

=>4X-Y=15

SUBTRACT EQUATION 2 FROM 1

==>4X-Y=15

--(3X-Y)=0

==>X=15