A father is now three times as old as his son.
Five years back, he was four times as old as
his son. The age of the son in years) is:
(A) 10
(B) 12
(C) 15
(D) 18
Answers
Step-by-step explanation:
- A father is now three times as old as his son.
- Five years back, he was four times as old as his son.
- The present age of son.
According to the 1st condition:-
A father is now three times as old as his son.
Let the present age of son be x
Present age of father = 3x
According the the 2nd condition:-
Five years back, he was four times as old as his son.
Five years ago:-
Age of son = Present age - 5
Age of son = x - 5
Age of father = Present age - 5
Age of father = 3x - 5
Father is four times as old as his son.
So:-
The present age of son = x = 15
The present age of father
= 3x
= 3 × 15
= 45
The present age of father = 45
Given:
Father is three times old as his son.
So,
Let the age of son be x years and
So the age of the father will be 3x years
Now,
According to the question:
Five years back, he was four times as old as his son,
Thus,
⇒ 3x - 5 = 4(x - 5)
⇒ 3x - 5 = 4x - 20
⇒ 20 - 5 = 4x - 3x
[By transporting (-20) to LHS and (3x) to RHS]
⇒ 15 = x
Therefore
The present age of the son is x years = 15 years.
So,
The correct option will be (C) 15
- - -
We can get the age of the father (present) = 3x = 3*15 = 45 years old.
Five years back his age will be (3x - 5) = 45 - 5 = 40 years old.
Five years back his son age will be (x-5) = 15 - 5 = 10 years old.
Now,
If we check their age according to the question we can verify their age
Five years back he was four times old as his son,
Son = 4(x - 5) = 4*10 = 40
Father = (3x - 5) = 45 - 5 = 40
Both RHS and LHS are equal.
Hence
Verified.