Question

A father is older than his son 30 years older than his son in 12 years the man will be 3 times as old as his son find their present ages​

Answer 1

Answer:

Solution:-

Let the present age of the son be 'x' years.

Then father's age will be (x + 30) years

Given : After 12 years, the father will be three times as old as his son. Therefore, 

(x + 12)3 = x + 30 + 12

3x + 36 = x + 42

3x - x = 42 - 36

2x = 6

x = 3 

The present age of son is 3 years and the present age of the father is 3 + 30 = 33 years.

Answer 2

Answer:

The present ages of son and father are 3 and 33 years respectively.

Step-by-step explanation:

Given:

Father is = 30 years older than his son

After 12 years = Father is thrice the age of his son.

To find :

Their present ages

Solution :

Let the present ages be -

• Son as x
• Father as (x + 30)

After 12 years old -

• Son = (x + 12)
• Father = (x + 30) + 12

According to the Question -

After 12 years the man will be = 3 times as old as his son

$\sf{\longrightarrow} \: (x + 30) + 12 = 3(x + 12) \\ \\ \sf{\longrightarrow} \: x + 42 = 3x + 36 \\ \\ \sf{\longrightarrow} \: 3x - x = 42 - 36 \\ \\ \sf{\longrightarrow} \: 2x = 6 \\ \\ \sf{\longrightarrow} \: x = \dfrac{6}{2} \\ \\ \sf{\longrightarrow} \: x = 3$

Son's present age = 3 years

$\rule{300}{1.5}$

★ Value of (x + 30)

$\sf{\longrightarrow} \: 3 + 30 \\ \\ \sf{\longrightarrow} \: 33$

Father is 33 years old.

$\therefore$ The present ages of son and father are 3 and 33 years respectively.