Question

A father is six times as old as his son. after 4 years he will be four times as old as his son will be. what are their present ages​

Answer 1

Answer:

Let the age of son be x so father's age would be 6x

Second condition

4(x+4)=6x+4

x=6 yrs

Sons age is 6 yrs

Father's age is 36 yrs

Step-by-step explanation:

this answer is correct

Answer 2

Answer:

let present age of son = x

so present age of father = 6x

their ages after 4 years = x+4 and 6x+4 respectively

according to question,

 6x+4 = 4(x+4)

6x + 4 = 4x + 16

so, by transposing

2x = 12

x = 6

THEREFORE, present age of son = x = 6 years

and present age of father = 6x = 36 years .

Hope this helped :)