Question

A father is six times as old as his son . After four years he will be only four times as old as his son will be. What are their present ages

Answer 1

Answer:

change your name first

Step-by-step explanation:

okay

Answer 2

Answer:

Father's age = 36 years

Son's age = 6 years

Step-by-step explanation:

Let represent the son's age with z,so the father's age would be 6z

After four years

6z + 4/z+4 = 4z/z

z(6z+4) = 4z(z+4)

6z²+4z= 4z²+16z

6z²-4z² = 16z - 4z

2z² = 12xz

2z = 12

z=6

Son's age= 6 yrs

Father's age = 36

                        OR YOU CAN USE THIS OTHER METHOD

METHOD 2

Let the age of son be y so father's age would be 6y

Second condition

4(y+4)=6y+4

4y + 16 = 6y +4

Collect like terms

16 - 4 = 6y -4y

12 = 2y

12/2 = y

6 = y

y=6 yrs

Sons age is 6 yrs

Father's age is 36 yrs