Question

A father is six times old as his son. 4 years hence he will be 4 times old as his son.Find their present ages.

Answer 1

Answer:

Step-by-step explanation:

X=6y

x+4=4(y+4)

x=?

y=?

x+4=4(y+4)

6y+4=4(y+4).       ( substituted x to term in y)

6y=4y+16-4

6y-4y=12

2y=12

y=6 yrs.  ( age of son )

x=6y

x=6*6

x=36 yrs (age of man)

hope my answer was helpful.

Answer 2

Answer:

Present Age of Father=36 years

Present Age of Son =6 years

Step-by-step explanation:

Hope it helps