A father is three time as old as his son in 14 years tme he will be twice as old as his son how old are they now
Answers
Answer:
41
Step-by-step explanation:
Let Present age of son be x.
Therefore, Present age of his father is 3x.
Their ages after 14 years,
Age of son = x + 14
Age of father = 3x + 14
2(x+14) = 3x+14
or, 2x + 28 = 3x + 14
or, x = 28 - 14 = 14
Hence,
Age of son = 14
Age of father = 3 * 14 = 41
Answer:
Present age of father is 42 years and son's age is 14 years
Step-by-step explanation:
Given : Father's age = 3 x son's age
after 14 years, father's age = 2 x son's age
Present age of father and son = ?
Solution : Let X be the age of son and Y be the age of father
given, Father's age = 3 x son's age
Y = 3X -----------------------1
after 14 years, father's age = 2 x son's age
Y +14 = 2 (X+14) -------------2
Substituting 1 in 2, we get
3X + 14 = 2(X+14)
3X +14 = 2X + 28
3X - 2X = 28-14
X = 14 years
Y = 3X
= 3 x 14
= 42 years
∴ Present age of father is 42 years and son's age is 14 years