A father is three time as old as his son is. After twelve years, his age will be twice as that of his son then. Find their present ages.
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FATHER =3X
SON=X
AFTER 12 YEARS
3X+12=FATHER
X+12=SON
SO
3X+12=2(X+12)
3X+12=2X+24
3X-2X=24-12
X=12
THEREFORE SON IS 12
FATHER IS 36
SON=X
AFTER 12 YEARS
3X+12=FATHER
X+12=SON
SO
3X+12=2(X+12)
3X+12=2X+24
3X-2X=24-12
X=12
THEREFORE SON IS 12
FATHER IS 36
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