A father is three times as old as his daughter and twice as old as his son and their total age is 88. How old is the son is.
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Let the age of the daughter be X
3x = fathers age
sons age is 3x/2
now 3x + X + 3x/2 =88
4x + 3x/2 = 88
LCM OF 2 & 1 = 2
(8x + 3x)/2 = 88
11x/2= 88
X = 44/11 = 4
hence:-
father 's age = 3x = 12.
daughter's age = X = 4.
son's age = 3x/2= 12/2= 6.
3x = fathers age
sons age is 3x/2
now 3x + X + 3x/2 =88
4x + 3x/2 = 88
LCM OF 2 & 1 = 2
(8x + 3x)/2 = 88
11x/2= 88
X = 44/11 = 4
hence:-
father 's age = 3x = 12.
daughter's age = X = 4.
son's age = 3x/2= 12/2= 6.
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