Question

a father is three times as old as his so 5 years ago fathers age was four times his sons age then find their present ages

Answer 1

Answer:

Let us assume that the father’s age is x and the son’s age is y.

According to the question, a father is now three times as old as his son,

so, x = 3y

five years before their ages would have been, x-5 and y-5. And the question says the father was four times as old as his son,

x-5 = 4( y -5)

x-5= 4y -20

x-4y + 15 = 0

3y - 4y + 15 =0 , we already know x = 3y

y = 15 and x = 45

The father is presently 45 and the son is 15

Answer 2

Let us assume that the father’s age is x and the son’s age is y.

According to the question, a father is now three times as old as his son,

so, x = 3y

five years before their ages would have been, x-5 and y-5. And the question says the father was four times as old as his son,

x-5 = 4( y -5)

x-5= 4y -20

x-4y + 15 = 0

3y - 4y + 15 =0 , we already know x = 3y

y = 15 and x = 45

The father is presently 45 and the son is 15

HOPE IT HELPS PLS MARK AS BRAINLIEST