Question

A father is three times as old as his son 15 years hence he will be twice as old as his son what is father's age​

Answer 1

$\huge\boxed{\mathtt\red{Solution :-}}$

Given :-

• father age three times the age of this son.
• After, 15 years he will the twice old as his son.

To Find :-

• Father's Age

Solving :-

◑ Let Father's age be x

◑ and age of son be y

According to the question :-

✒ x = 3y

________________________________

✒ (x+15) = 2(y+15)

✒ 3y+15 = 2y+30

✒ 3y-2y = 15

∴ y = 15

Now,

⟹ Father's age = x = 3y = 3×15 = 45 years.

Answer :-

$\large\boxed{\mathtt\green{∴The \:age\:of\:the\:father\:is\:45\:years}}$

Answer 2

Given Information :-

A father is three times as old as his son 15 years hence he will be twice as old as his son what is father's age ?

Solution :-

• Let us assume present age :

• Father's age = 3x years
• Son's age = y years

• After 15 years,

• Father's age = x + 15 years
• Son's age = 3x + 15 years

Now, according to question :-

→ 3x + 15 = 2(x + 15)

→ 3x + 15 = 2x + 30

→ 3x = 2x + 30 - 15

→ 3x = 2x + 15

→ 3x - 2x = 15

→ x = 15

Now,

Father's present age = 3x = 3 × 15 = 45

Hence,

• Father's age = 45 years.