Question

A father is three times as old as his son. 15 years hence, he will be twice as old as his son. What is the sum of their present ages?

Answer 1

Answer:

Let the present age of son be x years

Then, present age of other =3x years

After 15 years :

Son's age =(x+15) years

Father's age =(3x+15) years

But, according to the question.

⇒(3x+15)=2(x+15)

⇒3x+15=2x+30

⇒3x−2x=30−15

⇒x=15

∴ Son's age is 15 years.

Answer 2

Answer:

75

Step-by-step explanation:

x + 2x = 15

3x = 15

15/3

x = 5

5 * 5 = 25

25 * 2 = 50

25 + 50 = 75

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