a father is three times as old as his son 5years age father's age was four times his son's age then. find their present ages?
Answers
Answer:
45
Step-by-step explanation:
Let us assume that the father’s age is x and the son’s age is y.
According to the question, a father is now three times as old as his son,
so, x = 3y
five years before their ages would have been, x-5 and y-5. And the question says the father was four times as old as his son,
x-5 = 4( y -5)
x-5= 4y -20
x-4y + 15 = 0
3y - 4y + 15 =0 , we already know x = 3y
y = 15 and x = 45
The father is presently 45 and the son is 15
Answer:
let the father 's age is y
and the son's age is x.
according to question,
y=3x. ( equation 1)
and 5years ago,
we get,. (y-5)= 4 (x-5.) (equation 2)
and from equation 1 we have y=3x
put value in equation 2.
(3x-5)=4x-20
3x-5=4x-20
-x= -15
x=15
so, son age is 15 years and father age is 45.
hope it helps u dear ☺️☺️☺️