Math, asked by archana45240, 2 months ago

a father is three times as old as his son 5years age father's age was four times his son's age then. find their present ages?​

Answers

Answered by sohailkayani046
0

Answer:

45

Step-by-step explanation:

Let us assume that the father’s age is x and the son’s age is y.

According to the question, a father is now three times as old as his son,

so, x = 3y

five years before their ages would have been, x-5 and y-5. And the question says the father was four times as old as his son,

x-5 = 4( y -5)

x-5= 4y -20

x-4y + 15 = 0

3y - 4y + 15 =0 , we already know x = 3y

y = 15 and x = 45

The father is presently 45 and the son is 15

Answered by rahulkumarr179
0

Answer:

let the father 's age is y

and the son's age is x.

according to question,

y=3x. ( equation 1)

and 5years ago,

we get,. (y-5)= 4 (x-5.) (equation 2)

and from equation 1 we have y=3x

put value in equation 2.

(3x-5)=4x-20

3x-5=4x-20

-x= -15

x=15

so, son age is 15 years and father age is 45.

hope it helps u dear ☺️☺️☺️

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